Also sprach Ben Kosse:
} > Well the problem is bad 'C' code. It's not the compiler's fault. It's
} > just doing what it's told to do.
} >
} > char str[12]="mystring";
} >
} > declares a string on the stack with room for 12 bytes. However it is
} > initialized with only 9 (8 characters + the implied \0). So the rest
} > of the area has to be zeroed, which the compiler does.
} No it doesn't. For all C is required to care about, it could be stored as:
} "mystring\0bla" The definition is 12 bytes on the stack, the first nine being
} "mystring\0".
}
Depends on where the char str[12] is placed. If it is global, then it is
zeroed cause it's static...If it's an auto, then it can (and probably
does) have garbage after the terminating \0.
-- || Bill Wendling wendling@ganymede.isdn.uiuc.edu- To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to majordomo@vger.rutgers.edu Please read the FAQ at http://www.tux.org/lkml/
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