while ((mm->swap_cnt << 2 * (i + 1) < max_cnt) && i++ < 10)
/* nothing */;
I'm not that good at C, mas aren't expressions with side-effects ill-defined?
How can we be sure (short of tracking the gcc mailing lists) that i will be
incremented after the left part of the test?
I'd suggest
while (mm->swap_cnt << 2 * (i + 1) < max_cnt)
{
int j = i++;
if (!(j < 10))
break;
}
-- Cesar Eduardo Barros cesarb@web4u.com.br cesarb@dcc.ufrj.br- To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to majordomo@vger.rutgers.edu Please read the FAQ at http://www.tux.org/lkml/
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