David Howells <David.Howells@nexor.co.uk> said:
> Anyway, I though I could get away with it, but on reflection, perhaps
> not... If two threads of the same process try and issue ReleaseMutex()
> simultaneously on one mutex, then theoretically, one should succeed and the
> other fail, but given the above code, you are right... there would be a
Lost me there. If after releasing the mutex it is free, the release was
sucessful AFAIAC. If two threads try to do it at the same time, so what?
Releasing an already free mutex is broken, OK. But two threads owning the
mutex at the same time is much worse...
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This archive was generated by hypermail 2b29 : Thu Sep 07 2000 - 21:00:30 EST