Hi,
free is not an interesting command. Much more interesting is the kernel
messages on boot, e.g. on my laptop it looks like this:
BIOS-provided physical RAM map:
BIOS-e820: 000000000009fc00 @ 0000000000000000 (usable)
BIOS-e820: 0000000000000400 @ 000000000009fc00 (reserved)
BIOS-e820: 000000000000c000 @ 00000000000c0000 (reserved)
BIOS-e820: 0000000007ef0000 @ 0000000000100000 (usable)
BIOS-e820: 0000000000010000 @ 0000000007ff0000 (ACPI data)
BIOS-e820: 0000000000060000 @ 00000000100a0000 (reserved)
BIOS-e820: 0000000000200000 @ 00000000ffe00000 (reserved)
On node 0 totalpages: 32752
zone(0): 4096 pages.
zone(1): 28656 pages.
zone(2): 0 pages.
Kernel command line: auto BOOT_IMAGE=241 ro root=302
BOOT_FILE=/boot/vmlinuz-2.4.1
Initializing CPU#0
Detected 448.628 MHz processor.
Console: colour VGA+ 80x25
Calibrating delay loop... 894.56 BogoMIPS
kdb version 1.7 by Scott Lurndal, Keith Owens. Copyright SGI, All Rights
Reserved
Memory: 125696k/131008k available (1311k kernel code, 4924k reserved, 949k
data, 184k init, 0k highm
em)
as you can see, the above tells you exactly how many pages you have in
each zone and the total number of usable pages. But even that is not
relevant to your question. What is relevant is the number after the first
"/" in the "Memory:" line and also the BIOS-e820 map, of course.
Also, on 6.4G machine you should definitely use 64G i.e. PAE support and
so if not all memory is detected, please report to this list. People like
David Parsons will probably be interested in your configuration...
Regards,
Tigran
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This archive was generated by hypermail 2b29 : Fri Feb 23 2001 - 21:00:25 EST