Paul Flinders <paul@dawa.demon.co.uk> writes:
|> Andreas Schwab wrote:
|>
|> > This [isspace('\r') == 1] has no significance here. The right thing to
|>
|> > look at is $IFS, which does not contain \r by default. The shell only splits
|>
|> > words by "IFS whitespace", and the kernel should be consistent with it:
|> >
|> > $ echo -e 'ls foo\r' | sh
|> > ls: foo: No such file or directory
|>
|> The problem with that argument is that #!<interpreter> can be applied
|> to more than just shells which understand $IFS, so which environment
|> variable does the kernel pick?
The kernel should use the same default value of IFS as the Bourne shell,
ie. the same value you'll get with /bin/sh -c 'echo "$IFS"'. This is
independent of any settings in the environment.
|> It's a difficult one - logically white space should terminate the interpreter
No, IFS-whitespace delimits arguments in the Bourne shell.
Andreas.
-- Andreas Schwab "And now for something SuSE Labs completely different." Andreas.Schwab@suse.de SuSE GmbH, Schanzäckerstr. 10, D-90443 Nürnberg Key fingerprint = 58CA 54C7 6D53 942B 1756 01D3 44D5 214B 8276 4ED5 - To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to majordomo@vger.kernel.org More majordomo info at http://vger.kernel.org/majordomo-info.html Please read the FAQ at http://www.tux.org/lkml/
This archive was generated by hypermail 2b29 : Wed Mar 07 2001 - 21:00:19 EST