> Remember: we'd save 15*4=60 bytes per inode, at the cost of pinning the
> block the inode is in. But _usually_ we'd have those blocks in memory
> anyway, especially if the inode gets touched (which dirties it, and
> updates atime, which forces us to do writeback). For the initial IO we
> obviously _have_ to have them in memory.
Surely the buffer has the on disk inode format, not the fast to handle
in processor inode format ?
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This archive was generated by hypermail 2b29 : Sat Dec 15 2001 - 21:00:15 EST