Re: [PATCH] O16int for interactivity

From: Nick Piggin
Date: Mon Aug 18 2003 - 10:45:54 EST




Timothy Miller wrote:



Con Kolivas wrote:


A hardware timer interrupt happens at timeslice granularity. If the
interrupt occurs, but the timeslice is not expired, then NORMALLY, the
ISR would just return right back to the running task, but sometimes, it
might decided to end the timeslice early and run some other task.

Right?



No, the timeslice granularity is a hard cut off where a task gets rescheduled and put at the back of the queue again. If there is no other task of equal or better priority it will just start again.



Hmmm... I'm still having trouble making sense of this.

So, it seems that you're saying that all tasks, regardless of timeslice length, are interrupted every 10ms (at 100hz).


Interrupted - in that scheduler_tick is run, yes. They don't get switched.

If another task exists at a higher priority, then it gets run at that point.


Well loosely, yes. Actually, it happens if the task exists and is "running",
and has timeslice left. That only happens in scheduler_tick when the current
task has finished its timeslice and the priority arrays are about to be
switched. The required conditions for preemption can also occur when a task
is being woken up, (after sleeping or newly forked).

However, if there is more than one task at a given priority level, then they will not round-robin until the current task has used up all of its timeslice (some integer multiple of 10ms).


Thats right. Although I think Con or Ingo recently changed this in mm



Am I finally correct, or do I still have it wrong? :)


Sounds right to me.

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