Re: How much kernel memory is in 64-bit OS ?

[Jan Engelhardt]

>> > Sure, people said that too when going from 16 bits to 32 bits,
>> > but that was only a factor 2^16 difference.  This time it's the
>> > square of the previous difference.
>> 
>> Not quite the square :)
>
> 2^32 is the square of 2^16 :)

Going from 32 to 64:   (2^64 - 2^32)
Going from 16 to 32:   (2^32 - 2^16)

As mentioned above, "the square of the previos" [16 to 32] "difference". 
Call me nitpicky, but:

(2^32 - 2^16)^2  !=  (2^64 - 2^32)

>-- 
> What is important?  What you want to be true, or what is true?


Jan Engelhardt
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