Re: [PATCH] Allow a hyphenated range in get_options

[Randy Dunlap]

On Tue, 31 Oct 2006 11:25:16 -0600 Derek Fults wrote:

> This allows a hyphenated range of positive numbers in the string passed
> to command line helper function, get_options.    
> 
> Signed-off-by: Derek Fults <dfults@xxxxxxx>  

Hi,
Needs justification (why?) and a user.

> Index: linux/lib/cmdline.c
> ===================================================================
> --- linux.orig/lib/cmdline.c	2006-09-19 22:42:06.000000000 -0500
> +++ linux/lib/cmdline.c	2006-10-30 10:39:13.351641023 -0600
> @@ -29,6 +29,10 @@
>   *	0 : no int in string
>   *	1 : int found, no subsequent comma
>   *	2 : int found including a subsequent comma
> + *  -(int): int found with a subsequent hyphen to denote a range.
> + *          The negative number is the number of integers in the range
> + *          used to increment the counter in the while loop.
> + *      
>   */
>  
>  int get_option (char **str, int *pint)
> @@ -44,7 +48,16 @@
>  		(*str)++;
>  		return 2;
>  	}
> +	if (**str == '-') {
> +	    int x,inc_counter= 0, upper_range = 0;

space after comma.

Odd indentation here.  Use tabs, no spaces.

> +	    (*str)++;
> +	    upper_range = simple_strtol ((*str), NULL, 0);

No space after function name.

> +	    inc_counter = upper_range - *pint ;
> +	    for (x=*pint; x < upper_range; x++) 

No whitespace at ends of lines (as above has).
Space around '=' sign.

> +		    *pint++ = x;
> +	    return -inc_counter;
> +	}
>  	return 1;
>  }
>  
> @@ -55,7 +68,8 @@
>   *	@ints: integer array
>   *
>   *	This function parses a string containing a comma-separated
> - *	list of integers.  The parse halts when the array is
> + *	list of integers, a hyphen-separated range of _positive_ integers,
> + *      or a combination of both.  The parse halts when the array is

Fix indentation to be same as other lines.

>   *	full, or when no more numbers can be retrieved from the
>   *	string.
>   *
> @@ -75,6 +89,11 @@
>  		i++;
>  		if (res == 1)
>  			break;
> +		if (res < 0) 
> +		        /* Decrement the result by one to leave out the 
> +			   last number in the range.  The next iteration 
> +			   will handle the upper number in the range */
> +		        i += ((-res) - 1);
>  	}
>  	ints[0] = i - 1;
>  	return (char *)str;
> 
> -


---
~Randy
-
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