Re: [PATCH 2.6.19 5/5] fs: freeze_bdev with semaphore not mutex

From: Eric Sandeen
Date: Tue Nov 07 2006 - 18:19:01 EST


Rafael J. Wysocki wrote:
> On Tuesday, 7 November 2006 23:45, Eric Sandeen wrote:
>> Andrew Morton wrote:
>>
>>>> --- linux-2.6.19-rc4.orig/fs/buffer.c 2006-11-07 17:06:20.000000000 +0000
>>>> +++ linux-2.6.19-rc4/fs/buffer.c 2006-11-07 17:26:04.000000000 +0000
>>>> @@ -188,7 +188,9 @@ struct super_block *freeze_bdev(struct b
>>>> {
>>>> struct super_block *sb;
>>>>
>>>> - mutex_lock(&bdev->bd_mount_mutex);
>>>> + if (down_trylock(&bdev->bd_mount_sem))
>>>> + return -EBUSY;
>>>> +
>>> This is a functional change which isn't described in the changelog. What's
>>> happening here?
>> Only allow one bdev-freezer in at a time, rather than queueing them up?
>
> But freeze_bdev() is supposed to return the result of get_super(bdev)
> _unconditionally_. Moreover, in its current form freeze_bdev() _cannot_
> _fail_, so I don't see how this change doesn't break any existing code.

Well, it could return NULL. Is that a failure?

But, nobody is checking for an outright error, certainly. Especially
when the error hasn't been ERR_PTR'd. :) So I agree, that's not so good.

But, how is a stampede of fs-freezers -supposed- to work? I could
imagine something like a freezer count, and the filesystem is only
unfrozen after everyone has thawed? Or should only one freezer be
active at a time... which is what we have now I guess.

-Eric
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