Re: bitmap­_find_free_regio n and bitmap_full arg doubts

From: Komal Shah
Date: Fri Dec 01 2006 - 04:54:35 EST


On 12/1/06, Paul Jackson <pj@xxxxxxx> wrote:

M. R. Brown and Paul Mundt -- take a look at the question at end of this post.

Komal wrote:
>
> I have attached the test module code. I have confusion about the what
> to pass as second argument of bitmap_find_free_region for 2nd layer
> bitmap.
>
> Do we have to pass "total size of the block...here 128MB" as the
> second argument or no. of bits in that block, which 32768 (128 >>
> PAGE_SHIFT) ?
>
> This confusion arised as store queue implementation (sq.c) of sh arch,
> passes total size of the bitmap (64M) as the second argument instead
> of bits.
>
> Same is the case with bitmap_full, where I have to pass total size of
> the block (here 128MB) instead of no. of bits, in-order it to make my
> test module work correctly.

A bitmap is essentially an array of bits. The bitmap_* routines should
take a count of how many bits are in the bitmap array (or in your case,
how many bits are in the segment that you expect to be used in that call.)

So I'm guessing you will be passing L2_BM_BITS for that second argument.

The call to bitmap_find_free_region(), in arch/sh/kernel/cpu/sh4/sq.c
looks bogus:

page = bitmap_find_free_region(sq_bitmap, 0x04000000,
get_order(map->size));

It says the bitmap has 0x04000000 bits. This would take 0x04000000 / 8
which is 8388608 (decimal) bytes to hold. That's an insanely
huge bitmap - 8 million bytes worth of bits.

I can't make entire sense of the the code you attached. I get confused
over the various sizes of maps and what the maps represent, and of bits
and bytes, and of the two levels.

When you do call bitmap_find_free_region(), you should pass the number
of bits that are in that segment of the L2 bitmap, which I would guess
is L2_BM_BITS (32 K).

When you kzalloc() the L2 bitmap for all 16 segments at once, you
should pass the number of -bytes-, not the number of longs. That is,
I guess you want to replace your line:

bm_l2 = kzalloc(size * L1_BM_NUM_SEGS, GFP_KERNEL);

with the line:

bm_l2 = kzalloc(size * L1_BM_NUM_SEGS * sizeof(long), GFP_KERNEL);

This is because, like most of the *alloc() routines, kzalloc() takes
a byte count, not a long count. The related DECLARE_BITMAP() macro
computes the number of longs, not bytes, but that is because it is
declaring an array of longs, not allocating a number of bytes.

But I might be entirely confused about what this code is doing.

Oops, forgot to reply on this. This code is just a test module
in-order to go for layered bitmaps and in-turn understand bitmap_*
apis. As I said, requirement was to manage 2GB of virtual space of the
co-processor I have attached with ARM11. Now, as we can't allocate
single bitmap for 2GB, Paul Mundt suggested to have a layered bitmaps,
where 1st bitmap segmenting the virtual space into 128MB blocks and
have 2nd layer 128MB size bitmap for each segment in layer 1 bitmap.
Hope this clarifies the motivation behind it.

--
---Komal Shah
http://komalshah.blogspot.com
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