Re: [PATCH] lro: IP fragment checking

From: Andrew Gallatin
Date: Tue Dec 02 2008 - 10:36:44 EST


Ben Hutchings wrote:
On Tue, 2008-12-02 at 09:42 -0500, Andrew Gallatin wrote:
Ben Hutchings wrote:
On Mon, 2008-12-01 at 19:02 -0500, Andrew Gallatin wrote:
Ben Hutchings wrote:
[...]
If your hardware/firmware wrongly claims to be able to verify the
TCP/UDP checksum for an IP fragment, it seems to me you should deal with
that in your driver or fix the firmware.
We do partial checksums.
So you should check for IP fragmentation in your get_frag_header() along
with all the other checks you've got to do.
Indeed, and that is the patch I intend to submit if the fragment
check in inet_lro is rejected. I still think the check belongs
in the inet lro code though, and I'm worried it is being rejected
for the wrong reasons..

There's a wide variety of capabilities of different hardware:

1. No checksum offload. Probably not worth using LRO.
2. Full-checksum generation. Driver passes packets to inet_lro;
get_frag_header() or get_skb_header() parses packets to check that they
are TCP/IPv4 and to validate the checksum. inet_lro does further checks.
3. L4 packet parsing and checksum validation. Driver passes TCP/IPv4
packets to inet_lro. inet_lro does further checks.
4. Hardware/firmware LRO. inet_lro not needed.

You seem to be proposing that a check that is only needed in case (2)
should also be applied in case (3). Maybe it would make more sense to
define a generic implementation of get_frag_header() for full-checksum
devices, if that's possible?

Or maybe a generic lro_check_header() that can be called from
everybody's get_frag_header()/get_skb_header(). I guess what
bothers me is the division of checks between the get_*_header()
routine and lro_tcp_ip_checks() and the inevitable code
duplication in the get_*_header routines.

I still don't understand why an unneeded check for fragmentation
in case (3) is any more objectionable than the existing tcp
flags checks in lro_tcp_ip_check(), many of which are surely
not needed in case (3) either.

Drew
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