Re: Is adding requeue_delayed_work() a good idea

From: Dmitry Torokhov
Date: Mon Aug 31 2009 - 20:46:56 EST


On Wed, Aug 26, 2009 at 11:42:36AM -0700, Roland Dreier wrote:
>
> > OK, in this case I think we have a simple solution,
> >
> > // like cancel_delayed_work, but uses del_timer().
> > // this means, if it returns 0 the timer function may be
> > // running and the queueing is in progress. The caller
> > // can't rely on flush_workqueue/etc
> > static inline int __cancel_delayed_work(struct delayed_work *work)
> > {
> > int ret;
> >
> > ret = del_timer(&work->timer);
> > if (ret)
> > work_clear_pending(&work->work);
> > return ret;
> > }
> >
> > Now, you can do
> >
> > spin_lock_irqsave(&mydata_lock);
> > new_timeout = add_item_to_timeout_list();
> >
> > __cancel_delayed_work(&process_timeout_list_work);
> > queue_delayed_work(wq, &process_timeout_list_work, new_timeout);
> >
> > spin_unlock_irqsave(&mydata_lock);
> >
> > If queue_delayed_work() fails, this means that WORK_STRUCT_PENDING is set,
> > dwork->work is already queued or the queueing is in progress. In both
> > cases it will run "soon" as if we just called queue_work(&dwork->work).
>
> This looks like it would work well. If we can get this into 2.6.32 then
> I will drop my patch and switch to this approach instead.
>
> > But this assumes nobody else does queue_delayed_work(dwork, HUGE_DELAY) in
> > parallel, otherwise we can lose the race and another caller can setup
> > HUGE_DELAY timeout.
>
> In my case this is fine -- all uses of queue_delayed_work() are
> synchronized with the same lock. So any place that tries to shorten the
> timeout will succeed.
>

I can add the necessary locking in my case - I think it is actually needed
there even without this particular change.

--
Dmitry
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