sched: Am I missing something?

[Peter Williams]

Or is the line:

	p->prio = effective_prio(p);

in wake_up_new_task() an expensive no op.

As far as I can tell from reading the code, it will always be the case 
that EITHER rt_prio(p->prio) is true OR p->prio == p->normal_prio when 
this call is made and, in either case, the value of p->prio will be 
unchanged.  In addition, when this call is made p->normal_prio is 
already equal to to normal_prio(p), so the side effects of the function 
(setting p->normal_prio) are also unnecessary.

Am I correct or have I missed something?

Peter
--
Peter Williams                                   pwil3058@xxxxxxxxxxxxxx

"Learning, n. The kind of ignorance distinguishing the studious."
 -- Ambrose Bierce
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