Re: [PATCH 06/11] Export fragmentation index via/proc/extfrag_index

[Mel Gorman]

On Tue, Mar 23, 2010 at 09:22:04AM +0900, KOSAKI Motohiro wrote:
> > > > +	/*
> > > > +	 * Index is between 0 and 1 so return within 3 decimal places
> > > > +	 *
> > > > +	 * 0 => allocation would fail due to lack of memory
> > > > +	 * 1 => allocation would fail due to fragmentation
> > > > +	 */
> > > > +	return 1000 - ( (1000+(info->free_pages * 1000 / requested)) / info->free_blocks_total);
> > > > +}
> > > 
> > > Dumb question.
> > > your paper (http://portal.acm.org/citation.cfm?id=1375634.1375641) says
> > > fragmentation_index = 1 - (TotalFree/SizeRequested)/BlocksFree
> > > but your code have extra '1000+'. Why?
> > 
> > To get an approximation to three decimal places.
> 
> Do you mean this is poor man's round up logic?

Not exactly.

The intention is to have a value of 968 instead of 0.968231. i.e.
instead of a value between 0 and 1, it'll be a value between 0 and 1000
that matches the first three digits after the decimal place.

> Why don't you use DIV_ROUND_UP? likes following,
> 
> return 1000 - (DIV_ROUND_UP(info->free_pages * 1000 / requested) /  info->free_blocks_total);
> 

Because it's not doing the same thing unless I missed something.

-- 
Mel Gorman
Part-time Phd Student                          Linux Technology Center
University of Limerick                         IBM Dublin Software Lab
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