Re: [PATCH 1/3] padata: separate serial and parallel cpumasks

From: Dan Kruchinin
Date: Tue Jul 06 2010 - 04:31:36 EST


On Tue, Jul 6, 2010 at 11:46 AM, Steffen Klassert
<steffen.klassert@xxxxxxxxxxx> wrote:
> On Tue, Jul 06, 2010 at 11:40:11AM +0400, Dan Kruchinin wrote:
>> >> >
>> >>
>> >> I think we can use RCU anyway. For instance we could use a structure
>> >>
>> >> struct pcrypt_cpumask {
>> >>       cpumask_var_t           pmask;
>> >>       cpumask_var_t           smask;
>> >> };
>> >>
>> >> and add a pointer to a structure of that type to the instance context.
>> >> Then we could use this pointer for RCU and replace the whole structure
>> >> if a cpumask changes.
>>
>> But is pcrypt interested pmask? If it isn't, pmask field will be unused.
>>
>
> It's probaply not, in this case the struct could look like
>
> struct pcrypt_cpumask {
>        cpumask_var_t           smask;
> };
>

Would't it be the same as with a pointer to cpumask_var_t? I mean:
struct pcrypt {
...
struct pcrypt_cpumask *mask;
...
} pencrypt;

To assign a pointer via RCU:

int cpumask_change_nitify(...) {
...
struct pcrypt_cpumask *new_mask = kmalloc(sizeof(*mask), GFP);
struct pcrypt_cpumask *old_mask = pencrypt.mask;

if (!new_mask)
error();
if (!alloc_cpumask_var(&new_mask->smask, GFP_KERNEL))
error();

get_serial_cpumask_from_padata(new_mask->mask);
rcu_assign_pointer(pencrypt.mask, new_mask);
synchronize_rcu_bh();

free_cpumask_var(old_mask->smask);
kfree(old_mask);
...
}

It's a bit hard to read this code because at the first sight it
appears unclear and odd why we allocate the structure with only one
member.

--
W.B.R.
Dan Kruchinin
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