# Re: [PATCH 0/6] [RFC] Large weight differential leads toinefficient load balancing

From: Peter Zijlstra
Date: Mon Aug 02 2010 - 07:40:01 EST

On Thu, 2010-07-29 at 22:19 -0700, Nikhil Rao wrote:
> If folks think this is a good direction and this idea has some merit, then I
> will be more than happy to continue working with the community to improve this
> patchset. If there is another way to fix this problem, then please do tell; I
> would be more than happy to help out.

No its terrible. I've already explained how to solve this on several
occasions (although my google skillz seem to fail me to find the latest
occasion a few months ago).

The thing is that from a fairness point of view 1 nice-0 (weight=1024)
on one CPU and 512 SCHED_IDLE (weight=2) tasks on another CPU and all
other CPUs idle is correct.

It just doesn't seem to be the thing that most people expect.

Special casing things like you've done is utterly the wrong thing to do.

This problem comes in two forms and its name is infeasible weight
distribution. The load-balancer tries to ensure W_k ~= W_l, k,l elem_of
CPUs, where W_k = \Sum_i w_i^k, where w_i^k is the i-th task on CPU k.

The two cases are statically infeasible, and dynamically infeasible.

We say the task-set is statically infeasible if for a task set of n
tasks there is no way to statically distribute them on N <= n CPUs such
that each task gets equal service (assuming the scheduling on each CPU
is fair).

We say the task-set is dynamically infeasible if for the given scenario
there is no way to rotate the tasks to obtain equality.

Lets assume 2 CPUs.

Ex.1: 2 tasks of different weight.

Ex.2: 3 tasks of equal weight.

The first example is both statically and dynamically infeasible as there
is no way to occupy both CPUs such that each task gets the proportional
correct service.

The second example is statically infeasible, but dynamically feasible,
for if we rotate one task, such that we alternate between 2:1 and 1:2 in