Re: typecheck code
From: julie Sullivan
Date: Mon Jan 31 2011 - 16:42:52 EST
>If dummy and dummy2 are of different types, then when you try and do a
>pointer comparison (&dummy == &dummy2) it will produce a compiler
I came across this ages ago when I was trying to unravel the jiffies
wraparound macros and I've been scratching my head ever since trying
to figure out what this line _really_ did. A bit arcane, isn't it?
Thanks a lot Dave and everyone for explaining.
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