Re: Is __ffs64 supposed to be zero based?
From: Ben Greear
Date: Wed Nov 06 2013 - 12:17:12 EST
On 11/06/2013 03:52 AM, Clemens Ladisch wrote:
> Ben Greear wrote:
>> Similarly named methods elsewhere seem to indicate it is supposed to be
>> ones-based counting (ie, bit (1<<0) would be considred 'bit 1'.
> ffs() is defined to use one-based counting:
> __ffs() uses zero-based counting. On gcc, it's likely to be implemented
> with__builtin_ctz*(), whose documentation says:
> | Returns the number of trailing 0-bits in x, starting at the least
> | significant bit position.
Thanks for the information!
Ben Greear <greearb@xxxxxxxxxxxxxxx>
Candela Technologies Inc http://www.candelatech.com
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