Re: [PATCH] lib/checksum.c: fix carry in csum_tcpudp_nofold

From: Al Viro
Date: Tue Jan 27 2015 - 17:03:43 EST


On Tue, Jan 27, 2015 at 04:25:16PM +0100, Karl Beldan wrote:
> The carry from the 64->32bits folding was dropped, e.g with:
> saddr=0xFFFFFFFF daddr=0xFF0000FF len=0xFFFF proto=0 sum=1
>
> Signed-off-by: Karl Beldan <karl.beldan@xxxxxxxxxxxxxxxx>
> Cc: Mike Frysinger <vapier@xxxxxxxxxx>
> Cc: Arnd Bergmann <arnd@xxxxxxxx>
> Cc: linux-kernel@xxxxxxxxxxxxxxx
> Cc: Stable <stable@xxxxxxxxxxxxxxx>
> ---
> lib/checksum.c | 4 ++--
> 1 file changed, 2 insertions(+), 2 deletions(-)
>
> diff --git a/lib/checksum.c b/lib/checksum.c
> index 129775e..4b5adf2 100644
> --- a/lib/checksum.c
> +++ b/lib/checksum.c
> @@ -195,8 +195,8 @@ __wsum csum_tcpudp_nofold(__be32 saddr, __be32 daddr,
> #else
> s += (proto + len) << 8;
> #endif
> - s += (s >> 32);
> - return (__force __wsum)s;
> + s += (s << 32) + (s >> 32);
> + return (__force __wsum)(s >> 32);

Umm... I _think_ it's correct, but it needs a better commit message. AFAICS,
what we have is that s is guaranteed to be (a << 32) + b, with a being small.
What we want is something congruent to a + b modulo 0xffff. And yes, in case
when a + b >= 2^32, the original variant fails - it yields a + b - 2^32, which
is one less than what's needed. New one results first in
(a + b)(2^32+1)mod 2^64, then that divided by 2^32. If a + b <= 2^32 - 1,
the first product is less than 2^64 and dividing it by 2^32 yields a + b.
If a + b = 2^32 + c, c is guaranteed to be small and we first get
2^32 * c + 2^32 + 1, then c + 1, i.e. a + b - 0xffffffff, i.e.
a + b - 0x10001 * 0xffff, so the congruence holds in all cases.

IOW, I think the fix is correct, but it really needs analysis in the commit
message.
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