Re: [RFC v7 10/41] richacl: Permission check algorithm

From: J. Bruce Fields
Date: Thu Sep 17 2015 - 13:30:58 EST


On Sat, Sep 12, 2015 at 12:12:16AM +0200, Andreas GrÃnbacher wrote:
> 2015-09-11 23:16 GMT+02:00 J. Bruce Fields <bfields@xxxxxxxxxxxx>:
> > On Sat, Sep 05, 2015 at 12:27:05PM +0200, Andreas Gruenbacher wrote:
> >> + /*
> >> + * Apply the group file mask to entries other than owner@ and
> >> + * everyone@ or user entries matching the owner. This ensures
> >> + * that we grant the same permissions as the acl computed by
> >> + * richacl_apply_masks().
> >> + *
> >> + * Without this restriction, the following richacl would grant
> >> + * rw access to processes which are both the owner and in the
> >> + * owning group, but not to other users in the owning group,
> >> + * which could not be represented without masks:
> >> + *
> >> + * owner:rw::mask
> >> + * group@:rw::allow
> >> + */
> >> + if ((acl->a_flags & RICHACL_MASKED) && richace_is_allow(ace))
> >> + ace_mask &= acl->a_group_mask;
> >
> > I'm having trouble understanding this. I think the problem is that I
> > don't really understand the notation in your example. Is a_group_mask
> > zero in that example? I think it must be, in which case, OK I think I
> > get it.
>
> Yes. I'm not sure if the example becomes easier to understand when the
> empty group mask and perhaps also the other mask is included.

I think it would have been for me.

In general I find it confusing to present the mask bits as additional
ACEs--they're really pretty different.

> > (Though I still have to think about it a little more to convince myself
> > that richacl_apply_masks() always gets the same result.)
>
> I have tried to break the algorithm into digestible pieces. Do you see
> another way to make things easier to understand?

I just haven't reread those carefully enough yet, working on it....

--b.
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