Re: [PATCH V4 4/7] ARM64, ACPI, PCI: I/O Remapping Table (IORT) initial support.

From: Marc Zyngier
Date: Wed Apr 13 2016 - 11:23:16 EST


On 04/04/16 09:52, Tomasz Nowicki wrote:
> IORT shows representation of IO topology for ARM based systems.
> It describes how various components are connected together on
> parent-child basis e.g. PCI RC -> SMMU -> ITS. Also see IORT spec.
>
> Initial support allows to:
> - register ITS MSI chip along with ITS translation ID and domain token
> - deregister ITS MSI chip based on ITS translation ID
> - find registered domain token based on ITS translation ID
> - map MSI RID based on PCI device and requester ID
> - find domain token based on PCI device and requester ID
>
> To: Rafael J. Wysocki <rjw@xxxxxxxxxxxxx>
> Signed-off-by: Tomasz Nowicki <tn@xxxxxxxxxxxx>
> ---
> drivers/acpi/Kconfig | 3 +
> drivers/acpi/Makefile | 1 +
> drivers/acpi/iort.c | 335 ++++++++++++++++++++++++++++++++++++++++++++++++
> drivers/irqchip/Kconfig | 1 +
> include/linux/iort.h | 31 +++++
> 5 files changed, 371 insertions(+)
> create mode 100644 drivers/acpi/iort.c
> create mode 100644 include/linux/iort.h
>

[...]

> +static acpi_status
> +iort_find_dev_callback(struct acpi_iort_node *node, void *context)
> +{
> + struct acpi_iort_root_complex *pci_rc;
> + struct device *dev = context;
> + struct pci_bus *bus;
> +
> + switch (node->type) {
> + case ACPI_IORT_NODE_PCI_ROOT_COMPLEX:
> + bus = to_pci_bus(dev);
> + pci_rc = (struct acpi_iort_root_complex *)node->node_data;
> +
> + /*
> + * It is assumed that PCI segment numbers maps one-to-one
> + * with root complexes. Each segment number can represent only
> + * one root complex.
> + */
> + if (pci_rc->pci_segment_number == pci_domain_nr(bus))
> + return AE_OK;

What guarantees that this is ever valid? As far as I know, pci_domain_nr
is completely arbitrary, and depends both on the probe order and the
phase of the moon. If you want this to be reliable, you need to allocate
the domain number from pci_segment_number.

I must be missing something. Care to shed some light on this?

Thanks,

M.
--
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