[PATCH] MFD: do not assign already already assigned compatible of_nodes

[Valentin Longchamp]

If 2 similar cells have the same of_compatible (2 instances of the same
functionality), they both are assigned the first found of_node with this
compatible. In the below example, the pdev of both cells get the child@0
of_node.

parent@0 { /* MFD devices with 2 cells
	reg = <0>;
	child@0 {
		reg = <0>;
		compatible = "child-driver";
	};
	child@1 {
		reg = <1>;
		compatible = "child-driver";
	};
};

To avoid this, the found of_nodes are checked to see if they are already
assigned in the children of the parent dev and are only assigned if
still "available" (not assigned to a child).

This allows the 2nd cell's pdev to get the child@1 of_node.

Signed-off-by: Valentin Longchamp <valentin.longchamp@xxxxxxxxxxx>
---
 drivers/mfd/mfd-core.c | 19 +++++++++++++++++--
 1 file changed, 17 insertions(+), 2 deletions(-)

diff --git a/drivers/mfd/mfd-core.c b/drivers/mfd/mfd-core.c
index 3ac486a..11c5ded 100644
--- a/drivers/mfd/mfd-core.c
+++ b/drivers/mfd/mfd-core.c
@@ -137,6 +137,19 @@ static inline void mfd_acpi_add_device(const struct mfd_cell *cell,
 }
 #endif
 
+static inline int is_my_of_node(struct device *dev, void *data)
+{
+	struct device_node *np = data;
+
+	return dev->of_node == np;
+}
+
+static inline int of_node_already_in_children(struct device *dev,
+					      struct device_node *node)
+{
+	return device_for_each_child(dev, node, is_my_of_node);
+}
+
 static int mfd_add_device(struct device *parent, int id,
 			  const struct mfd_cell *cell, atomic_t *usage_count,
 			  struct resource *mem_base,
@@ -178,8 +191,10 @@ static int mfd_add_device(struct device *parent, int id,
 	if (parent->of_node && cell->of_compatible) {
 		for_each_child_of_node(parent->of_node, np) {
 			if (of_device_is_compatible(np, cell->of_compatible)) {
-				pdev->dev.of_node = np;
-				break;
+				if (!of_node_already_in_children(parent, np)) {
+					pdev->dev.of_node = np;
+					break;
+				}
 			}
 		}
 	}
-- 
1.8.3.1