Re: [PATCH 2/2 v2] sched: use load_avg for selecting idlest group

From: Vincent Guittot
Date: Fri Dec 02 2016 - 10:21:23 EST


On 30 November 2016 at 15:24, Morten Rasmussen <morten.rasmussen@xxxxxxx> wrote:
> On Wed, Nov 30, 2016 at 02:54:00PM +0100, Vincent Guittot wrote:
>> On 30 November 2016 at 14:49, Vincent Guittot
>> <vincent.guittot@xxxxxxxxxx> wrote:
>> > On 30 November 2016 at 13:49, Morten Rasmussen <morten.rasmussen@xxxxxxx> wrote:
>> >> On Fri, Nov 25, 2016 at 04:34:33PM +0100, Vincent Guittot wrote:
>> >>> find_idlest_group() only compares the runnable_load_avg when looking for
>> >>> the least loaded group. But on fork intensive use case like hackbench
>> >
>> > [snip]
>> >
>> >>> + min_avg_load = avg_load;
>> >>> + idlest = group;
>> >>> + } else if ((runnable_load < (min_runnable_load + imbalance)) &&
>> >>> + (100*min_avg_load > imbalance_scale*avg_load)) {
>> >>> + /*
>> >>> + * The runnable loads are close so we take
>> >>> + * into account blocked load through avg_load
>> >>> + * which is blocked + runnable load
>> >>> + */
>> >>> + min_avg_load = avg_load;
>> >>> idlest = group;
>> >>> }
>> >>>
>> >>> @@ -5470,13 +5495,16 @@ find_idlest_group(struct sched_domain *sd, struct task_struct *p,
>> >>> goto no_spare;
>> >>>
>> >>> if (this_spare > task_util(p) / 2 &&
>> >>> - imbalance*this_spare > 100*most_spare)
>> >>> + imbalance_scale*this_spare > 100*most_spare)
>> >>> return NULL;
>> >>> else if (most_spare > task_util(p) / 2)
>> >>> return most_spare_sg;
>> >>>
>> >>> no_spare:
>> >>> - if (!idlest || 100*this_load < imbalance*min_load)
>> >>> + if (!idlest ||
>> >>> + (min_runnable_load > (this_runnable_load + imbalance)) ||
>> >>> + ((this_runnable_load < (min_runnable_load + imbalance)) &&
>> >>> + (100*min_avg_load > imbalance_scale*this_avg_load)))
>> >>
>> >> I don't get why you have imbalance_scale applied to this_avg_load and
>> >> not min_avg_load. IIUC, you end up preferring non-local groups?
>> >
>> > In fact, I have keep the same condition that is used when looping the group.
>> > You're right that we should prefer local rq if avg_load are close and
>> > test the condition
>> > (100*this_avg_load > imbalance_scale*min_avg_load) instead
>>
>> Of course the correct condition is
>> (100*this_avg_load < imbalance_scale*min_avg_load)
>
> Agreed, I should have read the entire thread before replying :-)

Interestingly, the original condition (100*min_avg_load >
imbalance_scale*this_avg_load) gives better performance result for the
hackbench test than the new one : (100*this_avg_load <
imbalance_scale*min_avg_load)

Matt,

Have you been able to get some results for the patchset ?

Vincent