Re: [PATCH] pinctrl: rzn1: Add of_node_put() before return

From: Geert Uytterhoeven
Date: Mon Aug 05 2019 - 03:18:35 EST


CC Phil

On Sun, Aug 4, 2019 at 5:40 PM Nishka Dasgupta <nishkadg.linux@xxxxxxxxx> wrote:
> Each iteration of for_each_child_of_node puts the previous node, but in
> the case of a return from the middle of the loop, there is no put, thus
> causing a memory leak. Hence add an of_node_put before the return in
> three places.
> Issue found with Coccinelle.
>
> Signed-off-by: Nishka Dasgupta <nishkadg.linux@xxxxxxxxx>

Reviewed-by: Geert Uytterhoeven <geert+renesas@xxxxxxxxx>
i.e. will queue in sh-pfc-for-v5.4.

> ---
> drivers/pinctrl/pinctrl-rzn1.c | 12 +++++++++---
> 1 file changed, 9 insertions(+), 3 deletions(-)
>
> diff --git a/drivers/pinctrl/pinctrl-rzn1.c b/drivers/pinctrl/pinctrl-rzn1.c
> index cc0e5aa9128a..0f6f8a10a53a 100644
> --- a/drivers/pinctrl/pinctrl-rzn1.c
> +++ b/drivers/pinctrl/pinctrl-rzn1.c
> @@ -412,8 +412,10 @@ static int rzn1_dt_node_to_map(struct pinctrl_dev *pctldev,
>
> for_each_child_of_node(np, child) {
> ret = rzn1_dt_node_to_map_one(pctldev, child, map, num_maps);
> - if (ret < 0)
> + if (ret < 0) {
> + of_node_put(child);
> return ret;
> + }
> }
>
> return 0;
> @@ -792,8 +794,10 @@ static int rzn1_pinctrl_parse_functions(struct device_node *np,
> grp = &ipctl->groups[ipctl->ngroups];
> grp->func = func->name;
> ret = rzn1_pinctrl_parse_groups(child, grp, ipctl);
> - if (ret < 0)
> + if (ret < 0) {
> + of_node_put(child);
> return ret;
> + }
> i++;
> ipctl->ngroups++;
> }
> @@ -838,8 +842,10 @@ static int rzn1_pinctrl_probe_dt(struct platform_device *pdev,
>
> for_each_child_of_node(np, child) {
> ret = rzn1_pinctrl_parse_functions(child, ipctl, i++);
> - if (ret < 0)
> + if (ret < 0) {
> + of_node_put(child);
> return ret;
> + }
> }
>
> return 0;

Gr{oetje,eeting}s,

Geert

--
Geert Uytterhoeven -- There's lots of Linux beyond ia32 -- geert@xxxxxxxxxxxxxx

In personal conversations with technical people, I call myself a hacker. But
when I'm talking to journalists I just say "programmer" or something like that.
-- Linus Torvalds