Re: [PATCH 1/3] x86/debug: Fix BTF handling

From: Masami Hiramatsu
Date: Wed Oct 28 2020 - 20:56:57 EST


On Tue, 27 Oct 2020 20:41:26 +0100
Peter Zijlstra <peterz@xxxxxxxxxxxxx> wrote:

> On Tue, Oct 27, 2020 at 10:15:05AM +0100, Peter Zijlstra wrote:
>
> > @@ -873,6 +866,20 @@ static __always_inline void exc_debug_ke
> > */
> > WARN_ON_ONCE(user_mode(regs));
> >
> > + if (test_thread_flag(TIF_BLOCKSTEP)) {
> > + /*
> > + * The SDM says "The processor clears the BTF flag when it
> > + * generates a debug exception." but PTRACE_BLOCKSTEP requested
> > + * it for userspace, but we just took a kernel #DB, so re-set
> > + * BTF.
> > + */
> > + unsigned long debugctl;
> > +
> > + rdmsrl(MSR_IA32_DEBUGCTLMSR, debugctl);
> > + debugctl |= DEBUGCTLMSR_BTF;
> > + wrmsrl(MSR_IA32_DEBUGCTLMSR, debugctl);
> > + }
> > +
> > /*
> > * Catch SYSENTER with TF set and clear DR_STEP. If this hit a
> > * watchpoint at the same time then that will still be handled.
>
> Masami, how does BTF interact with !optimized kprobes that single-step?

Good question, BTF is cleared right before single-stepping and restored
after single-stepping. It will be done accoding to TIF_BLOCKSTEP bit as below.

(in arch/x86/kernel/kprobes/core.c)

static nokprobe_inline void clear_btf(void)
{
if (test_thread_flag(TIF_BLOCKSTEP)) {
unsigned long debugctl = get_debugctlmsr();

debugctl &= ~DEBUGCTLMSR_BTF;
update_debugctlmsr(debugctl);
}
}

static nokprobe_inline void restore_btf(void)
{
if (test_thread_flag(TIF_BLOCKSTEP)) {
unsigned long debugctl = get_debugctlmsr();

debugctl |= DEBUGCTLMSR_BTF;
update_debugctlmsr(debugctl);
}
}

Hrm, so it seems that we do same ... maybe we don't need clear_btf() too?

>
> The best answer I can come up with is 'poorly' :/

Is this what you expected? :)

Thank you,


--
Masami Hiramatsu <mhiramat@xxxxxxxxxx>