> On Wed, 31 Mar 1999, Rivalino Matias Junior wrote:
>
> > Okay. Try in C++ compiler (e.g. g++). I'm using g++ in this case.
>
> #include <stdio.h>
>
> void main() {
> int x = 0;
> int y = 1;
>
> x = (y) ? x = 1 : x = 2;
Which is
x = ( (y) ? x = 1 : x ) = 2
> I believe that gcc/egcc are buggy here - your code _should_ be legal.
> Also, whatever version of g++ you are using is _also_ buggy - it should be
> generating code to produce 1, not 2, but it is not.
Really? See above. ?: has *higher* priority than =. Depending on whether
the result of = is considered as l- or r-value it is either correct and
equivalent to
x = ( (y) ? (x = 1) , x : x ) = 2
i.e.
if (y) x=1;
x = x = 2;
or invalid (for r-value variant).
> I understand how ?: works. What I said was that gcc/egcc would not compile
> this line:
> x = (y) ? x = 1 : x = 2;
> But if you change it like this:
> x = (y) ? (x = 1) : (x = 2);
> then gcc/egcc don't give you an error. Try the same workaround in your own
> compiler, or upgrade it.
It's about the same "workaround" as for "WTF 1+1*1+1 is not 4 ???"
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