On 11/16/1999 12:04 -0500, Arni Raghu wrote:
>> Hi folks,
>> This is slightly OT but I thought only u kernel folks can answer this
>> better::
>>=09
>> Hi,
>> I am just playing with the shadow file (after making copies :) and teh c=
rypt
>> command..
>>=09
>> Here is a simple sequence that I perform..::
>>=09
>> useradd testme
>> passwd testme :: (passwd entered is testme2)
>>=09
>> then look into the shadow file and see::
>>=09
>> testme:$1$hI.ost8u$XZNxiISsD2ZuOrb6/Td3a/:10910:0:99999:7:-1:-1:134537888
>>=09
>> then using a simple perl script..I do $passwd =3D crypyt("testme2","$1");
>>=09
>> But the passwd I get is not the same as the one encoded in teh shadow
>> file...
>>=09
>> what is going on..I thought using the passwd and the salt I should be
>> getting back to the same encrypted passwd..why is this happening..
>>=09
>> something silly..???
>>=09
It's been a while since I've looked at this, but IIRC, the salt in this
case should be "$1$hI.ost8u$", not "$1"... the "$1$" identifies to the
crypt function to use the MD5 algorithm, rather than the DES variant, the
"hI.ost8u" portion is the actual salt, followed by another "$" terminator.
Using a salt string that does not start with "$1$" results in the legacy
DES variant crypt functionality.
I may not have gotten that all right, but it should give you someplace
to start - peruse the libc source for more details...
tw
--=20
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