1 start, 8 data, and 1 stop bit = 10 bits per transferred byte.
A standard ping packet contains 64 bytes -- 640 bits in this case.
Transferring 640 bits at 9600 bits per second would take ~0.067 seconds.
IOW, even with no other factors involved, it would take 67ms to cram the
entire ping packet through that pipe.
I'm with Glynn here -- if you're concerned about speed, consider a couple
cheapo network cards and a crossover cable.
On Friday 13 July 2001 05:44 pm, Michael Peddemors wrote:
> Glynn, you stumped me..
> Explain the 64*10 reasoning?
> On 13 Jul 2001 15:32:06 +0100, Glynn Clements wrote:
> > Clearly a 1ms ping (with the default packet size of 64 bytes) is
> > impossible over a 9600bps connection. Assuming 1 start bit and 1 stop
> > bit, the transmission time each way is 64 * 10 / 9600 = 0.067 = 67ms,
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This archive was generated by hypermail 2b29 : Sun Jul 15 2001 - 21:00:25 EST