Re: [PATCH] sched/debug: avoid executing show_state and causing rcu stall warning
From: Liu Song
Date: Wed Aug 03 2022 - 04:59:09 EST
* Liu Song <liusong@xxxxxxxxxxxxxxxxx> wrote:
From: Liu Song <liusong@xxxxxxxxxxxxxxxxx>
If the number of CPUs is large, "sysrq_sched_debug_show" will execute for
a long time. Every time I execute "echo t > /proc/sysrq-trigger" on my
128-core machine, the rcu stall warning will be triggered. Moreover,
sysrq_sched_debug_show does not need to be protected by rcu_read_lock,
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
and no rcu stall warning will appear after adjustment.
That doesn't mean it doesn't have to be protected by *any* lock - which
your patch implements AFAICS.
There's a couple of lines such as:
for_each_online_cpu(cpu) {
Hi,
Here I refer to the implementation of "sysrq_timer_list_show", and I
don't see any lock.
Maybe there is a problem with the implementation of "sysrq_timer_list_show".
Thanks
... which need to be protected against CPU hotplug events.
I haven't checked any of the deeper code to see what RCU or other
protection it may need, but clearly you didn't either ...
Thanks,
Ingo