Re: [PATCH v3 2/5] arm64: vdso: Implement __vdso_futex_robust_try_unlock()
From: André Almeida
Date: Mon Jun 01 2026 - 12:33:59 EST
Em 29/05/2026 14:47, Mathieu Desnoyers escreveu:
On 2026-05-29 12:33, André Almeida wrote:
Based on the x86 implementation, implement the vDSO function for unlocking
a robust futex correctly.
Commit xxxxxxxxxxxx ("x86/vdso: Implement __vdso_futex_robust_try_unlock()") has
the full explanation about why this mechanism is needed.
The unlock assembly sequence for arm64 is:
__vdso_futex_robust_list64_try_unlock:
retry:
ldxr w8, [x0] // Load the value from *futex
cmp w1, w8 // Compare with TID
b.ne __vdso_futex_list64_try_unlock_cs_end
stlxr w9, wzr, [x0] // Try to zero *futex
So it looks like stlxr can be successful, and the process is killed
right here. This is not within the start/end critical section, so the
fixup is missed ? Or am I missing something ?
As me and Mathieu discussed on IRC, this should be the right thing to do here:
- Move the critical section label one instruction above to include `cbnz` on it
- Use the result register as the check for the store success, not the zero flag register.
So it will look like this:
__vdso_futex_robust_list64_try_unlock:
retry:
ldxr w8, [x0] // Load the value from *futex
cmp w1, w8 // Compare with TID
b.ne __vdso_futex_list64_try_unlock_cs_end
stlxr w9, wzr, [x0] // Try to zero *futex
__vdso_futex_list64_try_unlock_cs_start:
cbnz w9, retry
str xzr, [x2] // After zeroing *futex, zero *op_pending
__vdso_futex_list64_try_unlock_cs_end>:
The decision regarding if the pointer should be cleared or not lies on checking the result register:
return (regs->user_regs[9]) ? NULL :
(void __user *) regs->user_regs.regs[2];
Thanks for the review!