[PATCH v3 1/2] sched_ext: Don't run ops.dequeue() with a DSQ lock held

[Qiurong Fang]

From: fangqiurong <fangqiurong@xxxxxxxxxx>

ops.dequeue() is invoked with the source user DSQ's lock still held on
the consume and move paths (scx_consume_dispatch_q(),
move_task_between_dsqs()). A BPF scheduler which locks the source user
DSQ from ops.dequeue() - e.g. by iterating it with bpf_iter_scx_dsq -
self-deadlocks.

ops.dequeue() can only call the "any" kfuncs and none of them can lock a
builtin DSQ, so the global and bypass paths can't deadlock; however,
all DSQ locks share one lockdep class, so iterating any user DSQ from
ops.dequeue() there trips the recursion check.

Move the invocation after the DSQ unlock on all three paths.
SCX_TASK_IN_CUSTODY is cleared under the lock serializing the transfer
so that the callback is invoked exactly once.

Fixes: ebf1ccff79c4 ("sched_ext: Fix ops.dequeue() semantics")
Cc: stable@xxxxxxxxxxxxxxx # v7.1+
Acked-by: Andrea Righi <arighi@xxxxxxxxxx>
Signed-off-by: fangqiurong <fangqiurong@xxxxxxxxxx>
---
 kernel/sched/ext/ext.c | 41 +++++++++++++++++++++--------------------
 1 file changed, 21 insertions(+), 20 deletions(-)

diff --git a/kernel/sched/ext/ext.c b/kernel/sched/ext/ext.c
index 40fa1697bdb7..b3aa2fb729a2 100644
--- a/kernel/sched/ext/ext.c
+++ b/kernel/sched/ext/ext.c
@@ -1499,27 +1499,22 @@ static inline bool task_scx_migrating(struct task_struct *p)
 	return p->scx.sticky_cpu >= 0;
 }
 
-/*
- * Call ops.dequeue() if the task is in BPF custody and not migrating.
- * Clears %SCX_TASK_IN_CUSTODY when the callback is invoked.
- */
-static void call_task_dequeue(struct scx_sched *sch, struct rq *rq,
-			      struct task_struct *p, u64 deq_flags)
+/* Must be called under the lock serializing @p's custody transfers. */
+static bool task_leave_custody(struct task_struct *p)
 {
 	if (!(p->scx.flags & SCX_TASK_IN_CUSTODY) || task_scx_migrating(p))
-		return;
-
-	if (SCX_HAS_OP(sch, dequeue))
-		SCX_CALL_OP_TASK(sch, dequeue, rq, p, deq_flags);
+		return false;
 
 	p->scx.flags &= ~SCX_TASK_IN_CUSTODY;
+	return true;
 }
 
 static void rq_owned_post_enq(struct scx_sched *sch, struct rq *rq,
 			      struct scx_dispatch_q *dsq, struct task_struct *p,
 			      u64 enq_flags)
 {
-	call_task_dequeue(sch, rq, p, 0);
+	if (task_leave_custody(p) && SCX_HAS_OP(sch, dequeue))
+		SCX_CALL_OP_TASK(sch, dequeue, rq, p, 0);
 
 	/*
 	 * Only local inserts get the wakeup treatment below. Rejects kick the
@@ -1705,20 +1700,28 @@ static void scx_dispatch_enqueue(struct scx_sched *sch, struct rq *rq,
 	if (is_rq_owned) {
 		rq_owned_post_enq(sch, rq, dsq, p, enq_flags);
 	} else {
+		bool call_dequeue = false;
+
 		/*
 		 * Global and bypass DSQs are terminal - the task leaves the
-		 * scheduler's custody, so ops.dequeue() fires here. It can run
+		 * scheduler's custody, so ops.dequeue() fires. It can run
 		 * without @p's rq lock (finish_dispatch() passes the dispatch
 		 * rq); that's safe because dequeue_task_scx() waits on
 		 * SCX_OPSS_DISPATCHING (see the ops_state note above) and so
 		 * can't race it. A non-terminal DSQ keeps the task in custody.
+		 * The custody transfer happens under @dsq->lock so that
+		 * later consumers see the flag clear; the callback runs
+		 * unlocked - it must not run with a DSQ lock held.
 		 */
 		if (dsq->id == SCX_DSQ_GLOBAL || dsq->id == SCX_DSQ_BYPASS)
-			call_task_dequeue(sch, rq, p, 0);
+			call_dequeue = task_leave_custody(p);
 		else
 			p->scx.flags |= SCX_TASK_IN_CUSTODY;
 
 		raw_spin_unlock(&dsq->lock);
+
+		if (call_dequeue && SCX_HAS_OP(sch, dequeue))
+			SCX_CALL_OP_TASK(sch, dequeue, rq, p, 0);
 	}
 
 	/*
@@ -2210,7 +2213,7 @@ static void ops_dequeue(struct rq *rq, struct task_struct *p, u64 deq_flags)
 		/*
 		 * A queued task must always be in BPF scheduler's custody. If
 		 * SCX_TASK_IN_CUSTODY is clear, finish_dispatch() on another
-		 * CPU has already passed call_task_dequeue() (which clears the
+		 * CPU has already passed task_leave_custody() (which clears the
 		 * flag), but has not yet written SCX_OPSS_NONE. That final
 		 * store does not require this rq's lock, so retrying with
 		 * cpu_relax() is bounded: we will observe NONE (or DISPATCHING,
@@ -2258,7 +2261,8 @@ static void ops_dequeue(struct rq *rq, struct task_struct *p, u64 deq_flags)
 	 * NONE but the task may still have %SCX_TASK_IN_CUSTODY set until
 	 * it is enqueued on the destination.
 	 */
-	call_task_dequeue(sch, rq, p, deq_flags);
+	if (task_leave_custody(p) && SCX_HAS_OP(sch, dequeue))
+		SCX_CALL_OP_TASK(sch, dequeue, rq, p, deq_flags);
 }
 
 static bool dequeue_task_scx(struct rq *rq, struct task_struct *p, int core_deq_flags)
@@ -2379,9 +2383,6 @@ void scx_move_local_task_to_local_dsq(struct scx_sched *sch, struct task_struct
 {
 	struct scx_dispatch_q *dst_dsq = scx_resolve_local_dsq(sch, dst_rq, p, &enq_flags);
 
-	/* @p is on @dst_rq, an rq-owned @src_dsq is covered by the rq lock */
-	if (!dsq_is_rq_owned(src_dsq))
-		lockdep_assert_held(&src_dsq->lock);
 	lockdep_assert_rq_held(dst_rq);
 
 	WARN_ON_ONCE(p->scx.holding_cpu >= 0);
@@ -2629,8 +2630,8 @@ static struct rq *move_task_between_dsqs(struct scx_sched *sch,
 		/* @p is going from a non-local DSQ to a local DSQ */
 		if (src_rq == dst_rq) {
 			scx_task_unlink_from_dsq(p, src_dsq);
-			scx_move_local_task_to_local_dsq(sch, p, enq_flags, src_dsq, dst_rq);
 			raw_spin_unlock(&src_dsq->lock);
+			scx_move_local_task_to_local_dsq(sch, p, enq_flags, src_dsq, dst_rq);
 		} else {
 			raw_spin_unlock(&src_dsq->lock);
 			move_remote_task_to_local_dsq(sch, p, enq_flags, src_rq, dst_rq);
@@ -2680,8 +2681,8 @@ bool scx_consume_dispatch_q(struct scx_sched *sch, struct rq *rq,
 
 		if (rq == task_rq) {
 			scx_task_unlink_from_dsq(p, dsq);
-			scx_move_local_task_to_local_dsq(sch, p, enq_flags, dsq, rq);
 			raw_spin_unlock(&dsq->lock);
+			scx_move_local_task_to_local_dsq(sch, p, enq_flags, dsq, rq);
 			return true;
 		}
 
-- 
2.43.0