Re: [RFC PATCH 1/5] mm/page_alloc: count guard pages as free again when their buddy merges
From: Zi Yan
Date: Wed Oct 14 2026 - 16:58:12 EST
On 6 Oct 2026, at 22:12, Rik van Riel wrote:
> With debug_guardpage_minorder set, expand() turns the unused halves of a
> split into guard pages, which page_del_and_expand() leaves out of the free
> counts. Freeing the allocated half credits only that half, and
> __free_one_page() then merges the guard buddy with clear_page_guard(),
> which no longer touches the counters.
>
> The merged block goes on a free list with the guard pages never counted,
> so NR_FREE_PAGES falls behind the free lists by every guard that merges.
> Before commit e0932b6c1f94 ("mm: page_alloc: consolidate free page
> accounting"), __set_page_guard() and __clear_page_guard() adjusted the
> counts themselves; that commit dropped both adjustments but kept the
> subtraction implicit in expand().
>
> Count the guard pages under the merged block's migratetype when the
> buddy is cleared. account_freepages() skips an isolated block as it does
> for every other free page, and moving the block off the isolated list
> counts it then.
>
> Booting a 16GB VM with debug_pagealloc=on debug_guardpage_minorder=1,
> check the difference in free pages reported between /proc/vmstat
> and /proc/buddyinfo.
>
> At three points (idle, after a read and file-creation load, after
> a second load), check the difference between nr_free_pages and the
> buddyinfo numbers in the normal zone, as a number of pages:
>
> idle after load after second load
> unpatched -130 79205 99121
> patched -16 45 0
>
> The small remaining difference seems to be due to the numbers
> not being read at exactly the same time, and is also seen
> without guard pages.
>
> Fixes: e0932b6c1f94 ("mm: page_alloc: consolidate free page accounting")
> Cc: stable@xxxxxxxxxxxxxxx
> Assisted-by: LLM
> Signed-off-by: Rik van Riel <riel@xxxxxxxxxxx>
> ---
> mm/page_alloc.c | 6 ++++--
> 1 file changed, 4 insertions(+), 2 deletions(-)
>
Good catch.
Reviewed-by: Zi Yan <ziy@xxxxxxxxxx>
Best Regards,
Yan, Zi