On Mon, 6 Nov 2000, RAJESH BALAN wrote:
> hi,
> why does this program works. when executed, it doesnt
> give a segmentation fault. when the program requests
> memory, is a standard chunk is allocated irrespective
> of the what the user specifies. please explain.
>
> main()
> {
> char *s;
> s = (char*)malloc(0);
malloc(0) is bogus in this case. malloc(0) == free();
> strcpy(s,"fffff");
> printf("%s\n",s);
> }
>
> NOTE:
> i know its a 'C' problem. but i wanted to know how
> this works
The most plausible reason is you're not crossing a page boundary, and you
don't get a access violation.
Igmar
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