On Thu, Dec 21, 2000 at 12:18:56PM -0600, Thomas Dodd wrote:
> Andrea Arcangeli wrote:
> >
> > On Fri, Dec 15, 2000 at 05:55:08PM -0200, Rik van Riel wrote:
> > > On Fri, 15 Dec 2000, Andrea Arcangeli wrote:
> > >
> > > > x()
> > > > {
> > > >
> > > > switch (1) {
> > > > case 0:
> > > > case 1:
> > > > case 2:
> > > > case 3:
> > > > ;
> > > > }
> > > > }
> > > >
> > > > Why am I required to put a `;' only in the last case and not in
> > > > all the previous ones?
> > >
> > > That `;' above is NOT in just the last one. In your above
> > > example, all the labels will execute the same `;' statement.
> > >
> > > In fact, the default behaviour of the switch() operation is
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
> > > to fall through to the next defined label and you have to put
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
> > > in an explicit `break;' if you want to prevent `case 0:' from
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
> > > reaching the `;' below the `case 3:'...
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
> >
> > Are you kidding me?
>
> Absolutely NOT.
>
> switch (x) {
> case 0:
> case 1:
> printf ("%d\n", x);
> break;
> case 2:
> printf ("%d\n",x*x);
> case 3:
> printf ("%d\n", x*x*x);
> }
>
> if x==0 or 1, prints x (the 0 or one),
> if x==2 , it prints 4 and 8 since no break statement exits the switch,
> if x==3, it prints only 27,
> any othe value of x, and nothing is printed.
>
> Every C compile I have ever used does this.
> Sun's C and C++, HP's C, Microsoft's VC++, Borland's C, and all versions
> of gcc and g++.
>
> Grab any C programming book, and find the switch statement.
What I need is an English book, not a C book ;). Chip told me I should have
written "Do you really think I don't know that?" while referring to the
underlined text. If it wasn't obvious I hope it's clear now. Thanks to Chip for
the English lesson.
Andrea
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