Le Wed, 2 May 2001 13:55:34 +0200
Ofer Fryman <ofer@shunra.co.il> à écrit :
> The definition of ioctl is "extern int __ioctl __P ((int __fd, unsigned long
> int __request, ...));" on Linux 2.0.x, and I believe it is also on any other
> Linux version.
yes but I use an network device specific ioctl call wich perform interface-specific
ioctl commands.
the prototype of the ioctl reception in the module is (as described in rubini book,
O reilly, linux device drivers):
int (*do_ioctl) (struct device *dev, struct ifreq *ifr, int cmd);
so can I pass over the limitations of the definition ?
I do ioctl that use private ioctl flags (e.g. SIOCDEVPRIVATE)
> So If you can pass what ever pointer or number you want instead of struct
> ifreq, If you use Linux under 2.2.x you will need to use copy_fromfs to get
> the buffer info, otherwise you can access it directly from the kernel mode
> with the restriction of interrupt handlers and bottom-halfs.
>
> -----Original Message-----
> From: sebastien.person@sycomore.fr [mailto:sebastien.person@sycomore.fr]
> Sent: Wednesday, May 02, 2001 10:08 AM
> To: liste noyau linux
> Subject: ioctl call for network device
>
>
> Hi,
>
> I've succeed to do an ioctl call and recept it in my module
>
> ioctl(file_descriptor, cmd, struct ifreq)
>
> but I believe that I'm oblige to use the struct ifreq and I can't
> pass any other arguments because an user can't acces kernel space
> so the ioctl call recopy data in the kernel space (this is what I've
> understood, maybe I'm wrong ...).
>
> My problem is that I need to pass some int arguments (the best way was an
> int* ) but the struct ifreq doesn't permit me it, so could I add other
> arguments as we can do in an normal ioctl call ?
>
> I hope this is the wrong place for this question.
>
> sebastien person
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This archive was generated by hypermail 2b29 : Mon May 07 2001 - 21:00:12 EST