>
> The Red Hat installation manual claims that the size of the swap partition
> should be twice the size of physical memory, but no more than 128MB.
This manual is outdated.
1. You hahe 2GB limit for a single swap file/partition now. And you can use
many of them.
2. it sjould be <= 2* RAM, i.e. 0 <= SWAP <= 2*RAM. More is inefficient.
3. except kernels 2.4.x, where x <= 7-ac8, where you should have SWAP=0 or
SWAP > RAM. 2.4.7-ac9 & 2.4.8 have already this problem fixed.
> The screaming hotrod machine Gary Sandine and I built around the Tyan S2464
> has 2GB of physical memory. Should I believe the above formula? If not,
> is there a more correct one for calculating needed swap on machines with
> very large memory?
Correct and universal formula for swap size is as always:
SWAP = MAX_RAM_you_ever_need - physical_RAM_you_have
However in 2.4 more eficient (and in 2.40-7 obligatory) is:
SWAP = MAX_RAM_you_ever_need > physical_RAM_you_have
? MAX_RAM_you_ever_need
;)
Andrzej
-
To unsubscribe from this list: send the line "unsubscribe linux-kernel" in
the body of a message to majordomo@vger.kernel.org
More majordomo info at http://vger.kernel.org/majordomo-info.html
Please read the FAQ at http://www.tux.org/lkml/
This archive was generated by hypermail 2b29 : Thu Aug 23 2001 - 21:00:31 EST