The difference in runtime between successive runs of your program
doesn't look terribly significant.
You open 'fd' each time, and never close it. I die about 1000 mmap()s
into the process (-EMFILE returned by sys_open). You may be testing
Linux' performance with huge fd sets in your test as well.
Moving the open() outside the loop, and running on a 512M, kernel 2.2
machine that's also running a full gnome desktop I get really intense
kernel CPU usage, and the following output:
10000 Time: 12
20000 Time: 45
30000 Time: 79
40000 Time: 113
[and I got too bored to watch it go on]
Unmapping the page after each map yields much better results:
10000 Time: 4
20000 Time: 4
30000 Time: 4
40000 Time: 5
50000 Time: 4
60000 Time: 4
70000 Time: 5
80000 Time: 5
90000 Time: 5
100000 Time: 4
[etc]
Interestingly, forcing the test to allocate at successively lower
addresses gives fast results until mmap fails (collided with a shared
library?):
10000 Time: 4
20000 Time: 4
30000 Time: 4
40000 Time: 4
50000 Time: 4
60000 Time: 4
Failed 0x60007000 12
So in kernel 2.2, it looks like some sort of linked list ordered by user
address is being traversed in order to complete the mmap() operation.
If so, then the O(N^2)-like behavior you saw in your original report is
explained as the expected performance of linux' mmap for a given # of
mappings.
Jeff
#include <stdio.h>
#include <unistd.h>
#include <sys/mman.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <errno.h>
int main()
{
int i = 0;
void *p;
int t;
int fd;
int addr = (void *) 0x70000000;
fd = open("test.dat", O_RDWR);
if (fd < 0) {
puts("Unable to open file !");
return;
}
t = time(NULL);
while (1) {
p = mmap(addr, 4096, PROT_READ | PROT_WRITE, MAP_PRIVATE, fd, 0);
addr = addr - 4096;
if ((int) p == -1) {
printf("Failed %p %d\n", addr, errno);
return;
}
i++;
if (i % 10000 == 0) {
printf(" %d Time: %d\n", i, time(NULL) - t);
t = time(NULL);
}
}
}
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This archive was generated by hypermail 2b29 : Fri Nov 30 2001 - 21:00:29 EST