On Friday 25 January 2002 00:13, Alexander Viro wrote:
> On 25 Jan 2002, Xavier Bestel wrote:
> > le sam 26-01-2002 à 00:09, Timothy Covell a écrit :
> > > #include <stdio.h>
> > >
> > > int main()
> > > {
> > > char x;
> > >
> > > if ( x )
> > > {
> > > printf ("\n We got here\n");
> > > }
> > > else
> > > {
> > > // We never get here
> > > printf ("\n We never got here\n");
> > > }
> > > exit (0);
> > > }
> > > covell@xxxxxx ~>gcc -Wall foo.c
> > > foo.c: In function `main':
> > > foo.c:17: warning: implicit declaration of function `exit'
> >
> > I'm lost. What do you want to prove ? (Al Viro would say you just want
> > to show you don't know C ;)
> > And why do you think you never get there ?
>
> I suspect that our, ah, Java-loving friend doesn't realize that '\0' is
> a legitimate value of type char...
>
> BTW, he's got a funny compiler - I would expect at least a warning about
> use of uninitialized variable.
Java lover's computer gcc -v says:
Reading specs from /usr/lib/gcc-lib/i386-redhat-linux/2.96/specs
gcc version 2.96 20000731 (Red Hat Linux 7.1 2.96-98)
I realize that '\0' is a legit character. And before you start,
I also realize that a string is a null terminated list of characters (yuck).
My point is to be clean about one's code. For example, Mark
Hahn sent me a bit of C based strlen code, but I prefer the
Linux kernel implementation which is more explicit and doesn't
make funky implicit nor explicit casts. Kernel code:
(And, of course, glibc uses Assembly for strlen).
#ifndef __HAVE_ARCH_STRLEN
/**
* strlen - Find the length of a string
* @s: The string to be sized
*/
size_t strlen(const char * s)
{
const char *sc;
for (sc = s; *sc != '\0'; ++sc)
/* nothing */;
return sc - s;
}
#endif
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