Linus Torvalds wrote:
> >> As long as your pointers are 32bit this seems to be ok. But on
> >> 64bit implementations pointers are not (unsigned long) so this cast
> >> seems to be wrong.
> >
> >A pointer fits into unsigned long on all 64bit linux ports.
> >The kernel very heavily relies on that.
>
> Not just the kernel, afaik. I think it's rather tightly integrated into
> gcc internals too (ie pointers are eventually just converted to SI
> inside the compiler, and making a non-SI pointer would be hard).
That can't be the case, as how would GCC represent 64-bit pointers on
platforms like the Alpha, which support 64-bit, 32-bit, 16-bit and 8-bit
types? 64-bits must be DImode simply because QImode is the smallest
mode, and required for the 8-bit type.
-- Jamie
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This archive was generated by hypermail 2b29 : Tue Jul 30 2002 - 14:00:17 EST