On Wed, 06 Aug 2003 21:26:30 EDT, Jeff Sipek said:
> > Can you really DO (x < y > z) and have it work as an anded pair of
> > comparisons? Maybe this is an addition to C that I am not aware of.
> >
> > I would expect (x < y > z) to be equivalent to ((x < y) > z).
>
> Ah, very true. I wonder what the author intended. Also, since the 'z' is 0 in
> all the cases, the statement "(i < TIMEOUT) > 0" can be reduced to "i <
> TIMEOUT".
Of course, if the author intended (x<y) && (x > 0), you can't reduce it if
x is at all possibly negative....
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