Re: [RFC] Use RCU for tcp_ehash lookup

[Srivatsa Vaddagiri]

On Wed, Sep 01, 2004 at 10:41:08PM -0700, David S. Miller wrote:
> The reason you don't see any improvement is that the ehash table is
> pretty write heavy.

In my simple one-file-transfer-test-at-a-time, it should have been read-mostly.
Probably the fact lookups are not serialized wrt input pakcet processing
may have shadowed the benefits of lock-free lookup. However perhaps
if I have multiple file transfer sessions in progress (one per cpu maybe),
then the benefit of reduced time spent in looking up a socket, could be passed 
on to threads doing network input.

> I'm not totally against your patch, I just don't think that the TCP established
> hash table qualifies as "read heavy" as per what RCU is truly effective for.

IMHO the benefits of lock-free will be seen only in such scenarios, i.e where
read_lock ended up having to spin-wait on a update to finish. In the lock-free 
case, there is no such wait.
 
> That's exactly what I was concerned about when I saw that you had attempted
> this change.  It is incredibly important for state changes and updates to
> be seen as atomic by the packet input processing engine.  It would be illegal
> for a cpu running TCP input to see a socket in two tables at the same time
> (for example, in the main established area and in the second half for TIME_WAIT
> buckets).
> 
> If the visibility of the socket is wrong, sockets could be erroneously
> be reset during the transition from established to TIME_WAIT state.
> Beware!

This is precisely the reason why I changed the order of movement in
__tcp_tw_hashdance. Earlier, it was removing the socket from the
established half and _then_ adding it to time-wait half. This would
have lead to a window where the socket is neither in established-half
not in the time-wait half. A packet arriving in this window (& doing
lock-free lookup) would have been dropped.

Hence I reversed the order of movement to add in time-wait first
before removing from established half.




> >   Note that __tcp_v4_lookup_established should not be affected by the above
> >   movement because I found it scans the established half first and _then_ the
> >   time wait half. So even if the same socket is present in both established half
> >   and time wait half, __tcp_v4_lookup_established will lookup only one of them
> >   (& not both).
> 
> I hope this is true.

AFAICS it is true! If __tcp_v4_lookup_established finds it in the established
half, it does no further lookup in the time-wait half.

-- 


Thanks and Regards,
Srivatsa Vaddagiri,
Linux Technology Center,
IBM Software Labs,
Bangalore, INDIA - 560017
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