Re: [RFC] Strange code in cpu_idle()
From: Zwane Mwaikambo
Date: Mon Dec 06 2004 - 04:52:57 EST
Hello Paul,
On Sat, 4 Dec 2004, Paul E. McKenney wrote:
> Unless idle_cpu() is busted, it seems like the above is, given the code in
> rcu_check_callbacks():
>
> void rcu_check_callbacks(int cpu, int user)
> {
> if (user ||
> (idle_cpu(cpu) && !in_softirq() &&
> hardirq_count() <= (1 << HARDIRQ_SHIFT))) {
> rcu_qsctr_inc(cpu);
> rcu_bh_qsctr_inc(cpu);
> } else if (!in_softirq())
> rcu_bh_qsctr_inc(cpu);
> tasklet_schedule(&per_cpu(rcu_tasklet, cpu));
> }
>
> And idle_cpu() is pretty straightforward:
>
> int idle_cpu(int cpu)
> {
> return cpu_curr(cpu) == cpu_rq(cpu)->idle;
> }
>
> So I would say that the rcu_read_lock() in cpu_idle() is having no
> effect, because any timer interrupt from cpu_idle() will mark a
> quiescent state notwithstanding. What am I missing here?
What about the hardirq_count check since we're coming in from the timer
interrupt?
> Note that we really, really do want the idle loop to be an extended
> quiescent state, otherwise one gets indefinite grace periods and
> runs out of memory...
I've (hopefully) covered this in another email.
Thanks,
Zwane
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