Re: Fortuna

[Matt Mackall]

On Sat, Apr 16, 2005 at 05:16:22PM -0000, linux@xxxxxxxxxxx wrote:
> > "How does the entropy estimator measure entropy of the event?" becomes a
> > crucial concern here.  What if, by your leading example, there is 1/2 bit
> > of entropy in each event?  Will the estimator even account for 1/2 bits?
> > Or will it see each event as 3 bits of entropy?  How much of a margin
> > of error can we tolerate?
> 
> H'm... the old code *used* to handle fractional bits, but the new code
> seems to round down to the nearest bit.  May have to get fixed to
> handle low-rate inputs.

I don't believe that was ever true, though it can fairly trivially be added.
JLC, please note that entropy estimation is much more conservative now
than it was a month ago.

> As for margin of error, any persistent entropy overestimate is Bad.
> a 6-fold overestimate is disastrous.
> 
> What we can do is refuse to drain the main pool below, say, 128 bits of
> entropy.  Then we're safe against any *occasional* overestimates
> as long as they don't add up to 128 bits.

I've been moving in that direction already, most of the infrastructure
is already in place.

> > /dev/random will output once it has at least 160 bits of entropy
> > (iirc), 1/2 bit turning into 3 bits would mean that 160bits of output
> > it effectively only 27 bits worth of true entropy (again, assuming the
> > catastrophic reseeder and output function don't waste entropy).
> > 
> > It's a lot of "ifs" for my taste.
> 
> /dev/random will output once it has as many bits of entropy as you're
> asking for.  If you do a 20-byte read, it'll output once it has 160
> bits.  If you do a 1-byte read, it'll output once it has 8 bits.

That's not quite right. It needs 8 bits in the relevant output pool.
Failing that, it needs 64 bits in the input pool to reseed the output
pool. In the case of /dev/urandom, it needs 128 bits in the input
pool, it always leaves enough for /dev/random to reseed.

-- 
Mathematics is the supreme nostalgia of our time.
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