Re: Hopefully, kmalloc() will always succeed, but if it doesn't then....

[Pekka Enberg]

On 10/22/06, Amit Choudhary <amit2030@xxxxxxxxx> wrote:
> So, if memory allocation to 'a' fails, it is going to kfree 'b'. But since 'b'
> is not initialized, kfree may crash (unless DEBUG is defined).
>
> I have seen the same case at many places when allocating in a loop.

So you found a bug. Why not send a patch to fix it?
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