RE: integer overflow in i2o_block

[Salyzyn, Mark]

I would change tid from an int to an unsigned instead, he is the culprit
that is promoting the unsigned to an signed.

Sincerely -- Mark Salyzyn

> -----Original Message-----
> From: linux-kernel-owner@xxxxxxxxxxxxxxx 
> [mailto:linux-kernel-owner@xxxxxxxxxxxxxxx] On Behalf Of Meelis Roos
> Sent: Thursday, July 26, 2007 4:30 PM
> To: Linux Kernel list
> Subject: integer overflow in i2o_block
> 
> 
> Got this warning on 32-bit ppc, seems real? And it seems I2O 
> subsystem has no maintainer (only DPT_I2O has one)?
> 
>   CC [M]  drivers/message/i2o/i2o_block.o
> drivers/message/i2o/i2o_block.c: In function 'i2o_block_transfer':
> drivers/message/i2o/i2o_block.c:837: warning: integer 
> overflow in expression
> 
> The line in question is
> msg->u.head[1] = cpu_to_le32(I2O_CMD_PRIVATE << 24 | HOST_TID 
> << 12 | tid);
> and I2O_CMD_PRIVATE is defined as 0xFF. This gets "0xFF0100 | 
> tid" and 
> fits into 32-bit unsigned but not into 32-bit signed integer properly.
> Target value head[*] is defined as u32 so the claculation 
> does not fit 
> during computation? Should we mark the shiftable inputas as unsigned?
> 
> -- 
> Meelis Roos (mroos@xxxxxxxx)
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