Re: [PATCH 0/24] make atomic_read() behave consistently across all architectures

[Paul Mackerras]

Herbert Xu writes:

> > You mean it's intended that *sk->sk_prot->memory_pressure can end up
> > as 1 when sk->sk_prot->memory_allocated is small (less than
> > ->sysctl_mem[0]), or as 0 when ->memory_allocated is large (greater
> > than ->sysctl_mem[2])?  Because that's the effect of the current code.
> > If so I wonder why you bother computing it.
> 
> You need to remember that there are three different limits:
> minimum, pressure, and maximum.  By default we should never
> be in a situation where what you say can occur.
> 
> If you set all three limits to the same thing, then yes it
> won't work as intended but it's still well-behaved.

I'm not talking about setting all three limits to the same thing.

I'm talking about this situation:

CPU 0 comes into __sk_stream_mem_reclaim, reads memory_allocated, but
then before it can do the store to *memory_pressure, CPUs 1-1023 all
go through sk_stream_mem_schedule, collectively increase
memory_allocated to more than sysctl_mem[2] and set *memory_pressure.
Finally CPU 0 gets to do its store and it sets *memory_pressure back
to 0, but by this stage memory_allocated is way larger than
sysctl_mem[2].

Yes, it's unlikely, but that is the nature of race conditions - they
are unlikely, and only show up at inconvenient times, never when
someone who could fix the bug is watching. :)

Similarly it would be possible for other CPUs to decrease
memory_allocated from greater than sysctl_mem[2] to less than
sysctl_mem[0] in the interval between when we read memory_allocated
and set *memory_pressure to 1.  And it's quite possible for their
setting of *memory_pressure to 0 to happen before our setting of it to
1, so that it ends up at 1 when it should be 0.

Now, maybe it's the case that it doesn't really matter whether
*->memory_pressure is 0 or 1.  But if so, why bother computing it at
all?

People seem to think that using atomic_t means they don't need to use
a spinlock.  That's fine if there is only one variable involved, but
as soon as there's more than one, there's the possibility of a race,
whether or not you use atomic_t, and whether or not atomic_read has
"volatile" behaviour.

Paul.
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