Re: [PATCH] Fix sched_domain sysctl registration again

From: Ingo Molnar
Date: Sun Oct 21 2007 - 03:43:40 EST



* Milton D. Miller II <miltonm@xxxxxxxxxxxx> wrote:

> commit 029190c515f15f512ac85de8fc686d4dbd0ae731 (cpuset
> sched_load_balance flag) was not tested SCHED_DEBUG enabled as
> committed as it dereferences NULL when used and it reordered the
> sysctl registration to cause it to never show any domains or their
> tunables.
>
> Fixes:
>
> 1) restore arch_init_sched_domains ordering
> we can't walk the domains before we build them
>
> presently we register cpus with empty directories (no domain
> directories or files).
>
> 2) make unregister_sched_domain_sysctl do nothing when already unregistered
> detach_destroy_domains is now called one set of cpus at a time
> unregister_syctl dereferences NULL if called with a null.
>
> While the the function would always dereference null if called
> twice, in the previous code it was always called once and then
> was followed a register. So only the hidden bug of the
> sysctl_root_table not being allocated followed by an attempt to
> free it would have shown the error.
>
> 3) always call unregister and register in partition_sched_domains
> The code is "smart" about unregistering only needed domains.
> Since we aren't guaranteed any calls to unregister, always
> unregister. Without calling register on the way out we
> will not have a table or any sysctl tree.
>
> 4) warn if register is called without unregistering
> The previous table memory is lost, leaving pointers to the
> later freed memory in sysctl and leaking the memory of the
> tables.

thanks, applied.

Ingo
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