struct user . u_ar0

[H. Peter Anvin]

I recently noticed that all architectures appear to have an entry n 
struct user called u_ar0:

  struct user_pt_regs * u_ar0;  /* Used by gdb to help find the values 
for */
                                /* the registers. */

In all cases, u_ar0 is a pointer type, although the type of pointer 
varies with the architecture.

However, under no conditions does this field ever contain a pointer 
value!  It is set by the a.out code and its derivatives as an offset, 
not a pointer value (there are a total of four references in the kernel, 
in arch/{m68k,blackfin}/kernel/process.c, arch/x86/ia32/ia32_aout.c and 
fs/binfmt_aout.c -- they are all functionally identical and write-only):

dump.u_ar0 = (void *)(((unsigned long)(&dump.regs)) - ((unsigned 
long)(&dump)));

Any reason to *NOT* change this field to "unsigned long"?  <asm/user.h>, 
where struct user is defined, is not exported to userspace in any 
architecture as far as I can tell, although <linux/user.h>, which just 
contains #include <asm/user.h>, *is* exported (clearly a bug.)

	-hpa


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