Re: Can Linux kernel handle unsynced TSC?
From: Peter Zijlstra
Date: Fri Feb 29 2008 - 09:27:44 EST
On Fri, 2008-02-29 at 22:20 +0800, Zhao Forrest wrote:
> On 2/29/08, Peter Zijlstra <peterz@xxxxxxxxxxxxx> wrote:
> >
> > On Fri, 2008-02-29 at 16:55 +0800, Zhao Forrest wrote:
> > > Sorry for reposting it.
> > >
> > > For example,
> > > 1 rdtsc() is invoked on CPU0
> > > 2 process is migrated to CPU1, and rdtsc() is invoked on CPU1
> > > 3 if TSC on CPU1 is slower than TSC on CPU0, can kernel guarantee
> > > that the second rdtsc() doesn't return a value smaller than the one
> > > returned by the first rdtsc()?
> >
> > No, rdtsc() goes directly to the hardware. You need a (preferably cheap)
> > clock abstraction layer on top if you need this.
>
> Thank you for the clarification. I think gettimeofday() is such kind
> of clock abstraction layer, am I right?
Yes, gtod is one such a layer, however it fails the 'cheap' test for
many definitions of cheap.
--
To unsubscribe from this list: send the line "unsubscribe linux-kernel" in
the body of a message to majordomo@xxxxxxxxxxxxxxx
More majordomo info at http://vger.kernel.org/majordomo-info.html
Please read the FAQ at http://www.tux.org/lkml/